Step of Proof: bool-to-neg-dcdr-aux 11,40

Inference at * 
Iof proof for Lemma bool-to-neg-dcdr-aux:


  A:Type, f:(A), x:A. Dec(f(x) = ff) 
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 by Auto 
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DefinitionsDec(P), s = t, x:AB(x), f(a), ff, x:AB(x), , t  T, Type
Lemmasdecidable equal bool, bfalse wf, bool wf

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